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Downloaded from www.gateonlinex.com EE-Paper Code-A GATE 2011 Q. No. 1 – 25 Carry One Mark Each Roots of the algebraic equation x3 + x2 + x + 1 = 0 are (A) ( +1, + j, − j) Answer: - (D) Exp: - x3 + x2 + x + 1 = 0 ⇒ x2 + 1 ( x + 1) = 0 (B) ( +1, −1, +1) (C) (0,0,0) (D) ( −1, + j, − j) www.gateforum.com 1. ( ) ⇒ x + 1 = 0; x2 + 1 = 0 ⇒ x = −1 x = ±j 2. With K as a constant, the possible solution for the first order differential equation dy = e−3x is dx (A) − 1 −3x e +K 3 (B) − 1 3x e +K 3

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GATE EE 2011 QUESTIONS